Calculus Solutions Ex#2.2

  Q.07 Solution: Given $$ \begin{aligned} & m=f^{\prime}(3)=5 \\ \\ & x_{1}=3, \quad y_{1}=f(3)=-1 \end{aligned} $$ Equation of tangent line $$ \begin{aligned} y-y_{1} & =m\left(x-x_{1}\right) \\ \\ y-(-1) & =5(x-3) \\ \\ y+1 & =5(x-3) \\ \\ y & +1=5 x-15 \\ \\ y & =5 x-15-1 \\ \\ y & =5 x-16 \end{aligned} $$ … Read more