Calculus Solutions Ex#2.6

  [embeddoc url=”https://genesismath.com/wp-content/uploads/2023/04/EXERCISE-2.6.pdf” viewer=”google”] Q.01 Solution: Given that $f^{\prime}(0)=2, g(0)=0$ and $g^{\prime}(0)=3$  find  $(f \circ g)^{\prime}(2).$  $$ \begin{aligned}  \text {Formula} (f \circ g)^{\prime}(x)=f^{\prime}(g(x)) g^{\prime}(x) \quad \text { Put } x=0, \end{aligned}$$  $$ \begin{aligned}(f \circ g)^{\prime}(0) & =f^{\prime}(g(0)) g^{\prime}(0) & & \\ \\ & =f^{\prime}(0) \cdot(3) & \therefore g(0) =0 \\ \\ & =2(3)=6 & & … Read more